DISTRIBUTIVE LAW FOR
DOT PRODUCT | ||
| According to distributive law for dot product: | ||
PROOF
| ||
| Consider three vectors The dot product | ||
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Showing posts with label Chemical Bonds. Show all posts
Showing posts with label Chemical Bonds. Show all posts
DISTRIBUTIVE LAW FOR DOT PRODUCT
AREA OF PARALLELOGRAM
COMMUTATIVE LAW
OF VECTOR ADDITION | ||
| Consider two vectors | ||
| OACB as shown in the diagram. The diagonal OC represents the resultant vector | ||
| From above figure it is clear that: | ||
| This fact is referred to as the commutative law of vectr addition . | ||
ASSOCIATIVE LAW
OF VECTOR ADDITION | ||
| The law states that the sum of vectors remains same irrespective of their order or grouping in which they are arranged. Consider three vectors | ||
| Applying "head to tail rule" to obtain the resultant of ( | ||
| Then finally again find the resultant of these three vectors : | ||
| This fact is known as the ASSOCIATIVE LAW OF VECTOR ADDITION. | ||
KINEMATICS
KINEMATICS
| ||
"Kinematics is the branch of Physics in which we discuss bodies at rest or motion
without the reference of external agent that causes motion or rest." OR "The branch of physics which deals with the description of motion of objects without reference to the force or agent causing motion in it, is called Kinematics." | ||
REST
| ||
"If a body does not change its position with respect to its surroundings then
the body is said to be in a state of rest." | ||
MOTION
| ||
"If a body continuously changes its position with respect to its surrounding
than it is said to be in a state of motion." | ||
TYPES OF MOTION
| ||
| Motion of objects can be divided into three categories. | ||
| (i) TRANSLATIONAL MOTION (ii) ROTATIONAL MOTION (iii) VIBRATIONAL MOTION | ||
TRANSLATIONAL MOTION
| ||
"Motion of a body in which every particle of the body is being
displaced by the same amount is called Translational Motion". | ||
| EXAMPLE: (i) Motion of a person on a road. (ii) Motion of a car or truck on a road. | ||
ROTATIONAL MOTION
| ||
"Type of motion in which a body rotates around a
fixed point or axis is called Rotational Motion." | ||
| EXAMPLE: (i) Motion of wheel (ii) Motion of the blades of a fan | ||
VIBRATIONAL MOTION
| ||
"Type of motion in which a body or particle moves to and fro
about a fixed point or mean position is called Vibratory Motion." | ||
| EXAMPLE: (i) Motion of simple pendulum (ii) Motion of the wires of guitar (iii) Motion of swing | ||
DISPLACEMENT
| ||
"Distance between two points in a particular direction is called Displacement."
OR Displacement may also be defined as "the minimum distance between two points in a particular direction." | ||
| It is a vector quantity and is always directed from the initial point to the terminal point. It is denoted by "d". | ||
SPEED
| ||
"Distance covered by a moving body in one second is called its Speed".
OR "Distance covered by a body in unit time is called Speed". | ||
| Speed is a scalar quantity. | ||
FORMULA
| ||
Speed = Distance traveled/Time taken
OR v = S/t | ||
UNIT
| ||
| Unit of speed in S.I system is "m/sec". | ||
VELOCITY
| ||
"Distance covered by a body in a particular direction in one second is called Velocity".
OR "Displacement of a body in unit time is called Velocity". OR "Change of position of a body per second in a particular direction is called Velocity." | ||
FORMULA
| ||
velocity = displacement/time
| ||
UNIT
| ||
| In S.I system unit of velocity is meter/second. It is a vector quantity. | ||
ACCELERATION
| ||
"The rate of change of velocity of a body is called Acceleration."
OR "Change in velocity of a body in unit time is called its acceleration." | ||
| It is denoted by "a". It is a vector quantity. If a body moves with uniform velocity or constant velocity then its acceleration will be zero. UNIT: m/sec2. | ||
FORMULA
| ||
Acceleration = change in velocity/time
OR a = DV/t | ||
RESOLUTION OF VECTOR
DEFINITION
| ||
| The process of splitting a vector into various parts or components is called "RESOLUTION OF VECTOR" | ||
| These parts of a vector may act in different directions and are called "components of vector". | ||
| We can resolve a vector into a number of components .Generally there are three components of vector viz. Component along X-axis called x-component Component along Y-axis called Y-component Component along Z-axis called Z-component | ||
| Here we will discuss only two components x-component & Y-component which are perpendicular to each other.These components are called rectangular components of vector. | ||
METHOD OF RESOLVING
A VECTOR INTO RECTANGULAR COMPONENTS | ||
| Consider a vector represented by a line OA.From point A draw a perpendicular AB on X-axis.Suppose OB and BA represents two vectors.Vector OA is parallel to X-axis and vector BA is parallel to Y-axis.Magnitude of these vectors are Vx and Vy respectively.By the method of head to tail we notice that the sum of these vectors is equal to vector Vx = Horizontal component of Vy = Vertical component of | ||
MAGNITUDE OF
HORIZONTAL COMPONENT | ||
| Consider right angled triangle DOAB | ||
MAGNITUDE OF
VERTICAL COMPONENT | ||
| Consider right angled triangle DOAB | ||
LAW OF CONSERVATION OF ENERGY
LAW OF CONSERVATION OF ENERGY
| ||
| According to the law of conservation of energy : "Energy can neither be created nor it is destroyed, however energy can be converted from one form energy to any other form of energy" | ||
| SHOW THAT THE MOTION OF A SIMPLE PENDULUM IS ACCORDING TO THE LAW OF CONSERVATION ENERGY. OR PROVE THE LAW OF CONSERVATION WITH THE HELP OF A SUITABLE EXAMPLE. | ||
| We know that the motion of the bob of a simple pendulum is simple harmonic motion. Here we have to prove that the energy is conversed during the motion of pendulum. Proof: Consider a simple pendulum as shown in the diagram. | ||
Energy Conservation At Point ‘A’
| ||
| At point ‘A’ velocity of the bob of simple pendulum is zero. Therefore, K.E. at point ‘A’ = 0. Since the bob is at a height (h), Therefore, P.E. of the bob will be maximum. i.e. P.E. = mgh. Energy total = K.E. + P.E Energy total = 0 + mgh Energy total = mgh This shows that at point A total energy is potential energy. | ||
Energy Conservation At Point ‘M’
| ||
| If we release the bob of pendulum from point ‘A’, velocity of bob gradually increases, but the height of bob will decreases from point to the point. At point ‘M’ velocity will become maximum and the height will be nearly equal to zero. Thus , K.E. = maximum = 1/2mV2 but P.E. = 0. Energy total = K.E. + P.E Energy total = 1/2mV2 + 0 Energy total = 1/2mV2 This shows that the P.E. at point is completely converted into K.E. at point ‘M’. | ||
Energy Conservation At Point ‘B’
| ||
| At point M the bob of Pendulum will not stop but due to inertia, the bob will moves toward the point ‘B’. As the bob moves from ‘M’ to ‘B’, its velocity gradually decreases but the height increases. At point ‘B’ velocity of the bob will become zero. Thus K.E. at point ‘B’ = 0 but P.E. = max. P.E. = mgh. Energy total = K.E. + P.E. Energy total = 0 + mgh Energy total = mgh This shows that at point B total energy is again potential energy. | ||
CONCLUSION
| ||
| Above analysis indicates that the total energy during the motion does not change. I.e. the motion of the bob of simple pendulum is according to the law of conservation of energy. | ||
ENERGY
ENERGY
| ||
| "The ability of a body to perform work is called Energy". | ||
| A body cannot perform work if it does not posses energy.A body cannot perform work more than the amount of energy. | ||
| It is a scalar quantity. | ||
UNITS OF ENERGY
| ||
| (i) Joule (ii) Calorie [NOTE: 1 Calorie = 4.2 joule.] (iii) KWatt-Hour | ||
TYPES OF ENERGY
| ||
| There aree numerous types of energy such as: | ||
POWER
| ||
"The rate of work done of a body is called Power".
| ||
AVERAGE POWER
| ||
| Average power of a body doing work is numerically equal to the totla work done divided by the time taken to perform the work. | ||
MATHMATICALLY
| ||
Power = Work done/time
Power = Work/t but [work = Fd] therefore Power = Fd/t | ||
UNITS OF POWER
| ||
| (i) watt [1 watt = 1joule/sec ] (ii) Kilo watt [1Kw = 1000 watt] (iii) Mega watt (Mw) [1Mw = 106 watt] (iv) Horse power [1Hp = 746w] | ||
| POTENTIAL ENERGY | ||
INTRODUCTION
| ||
| Energy stored by a body by any means is called "Potential Energy". | ||
DEFINITION
| ||
| "The energy stored by a body due to its position in gravitational field is known as ‘Gravitational Potential Energy’". | ||
FORMULA
| ||
| Consider a body of mass "m" placed at a height of "h" from the surface of earth. Force = Weight = W but displacement (d) = h | ||
Work done = Fd
OR Work done = Wh [but W = mg] | ||
| work done = mgh WE know that the work done in lifting the body is stored in the body in the form of Potential Energy. Thus P.E. = mgh | ||
Nomenclature of Simple Alkene Chain Molecules
Simple Alkene Chains
An alkene is a molecule made up entirely of carbon and hydrogen where on or more carbon atoms are connected by double bonds. The general formula for an alkene is CnH2n where n is the number of carbon atoms in the molecule.Alkanes are named by adding the the -ene suffix to the prefix associated with the number of carbon atoms present in the molecule. A number and dash before the name denotes the number of the carbon atom in the chain that begins the double bond.
For example: 1-hexene is a six carbon chain where the double bond is between the first and second carbon atoms.
Click image to enlarge the molecule.
Ethene
Number of Carbons: 2
Prefix: eth- Number of Hydrogens: 2(2) = 4
Molecular Formula: C2H4
Prefix: eth- Number of Hydrogens: 2(2) = 4
Molecular Formula: C2H4
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Propene
Number of Carbons: 3
Prefix: prop- Number of Hydrogens: 2(3)= 6
Molecular Formula: C3H6
Prefix: prop- Number of Hydrogens: 2(3)= 6
Molecular Formula: C3H6
Butene
Number of Carbons: 4
Prefix: but- Number of Hydrogens: 2(4) = 8
Molecular Formula: C4H8
Prefix: but- Number of Hydrogens: 2(4) = 8
Molecular Formula: C4H8
Pentene
Number of Carbons: 5
Prefix: pent- Number of Hydrogens: 2(5) = 10
Molecular Formula: C5H10
Prefix: pent- Number of Hydrogens: 2(5) = 10
Molecular Formula: C5H10
Hexene
Number of Carbons: 6
Prefix: hex- Number of Hydrogens: 2(6)= 12
Molecular Formula: C6H12
Prefix: hex- Number of Hydrogens: 2(6)= 12
Molecular Formula: C6H12
Heptene
Number of Carbons: 7
Prefix: hept- Number of Hydrogens: 2(7) = 14
Molecular Formula: C7H14
Prefix: hept- Number of Hydrogens: 2(7) = 14
Molecular Formula: C7H14
Octene
Number of Carbons: 8
Prefix: oct- Number of Hydrogens: 2(8) = 16
Molecular Formula: C8H16
Prefix: oct- Number of Hydrogens: 2(8) = 16
Molecular Formula: C8H16
Nonene
Number of Carbons: 9
Prefix: non- Number of Hydrogens: 2(9) = 18
Molecular Formula: C9H18
Prefix: non- Number of Hydrogens: 2(9) = 18
Molecular Formula: C9H18
Decene
Number of Carbons: 10
Prefix: dec- Number of Hydrogens: 2(10) = 20
Molecular Formula: C10H20
Prefix: dec- Number of Hydrogens: 2(10) = 20
Molecular Formula: C10H20
Isomer Numbering Scheme
These three structures illustrate the numbering scheme for isomers of alkene chains. The carbon atoms are numbered from left to right. The number represents the location of the first carbon atom that is part of the double bond.
In this example: 1-hexene has the double bond between carbon 1 and carbon 2, 2-hexene between carbon 2 and 3, and 3-hexene between carbon 3 and carbon 4.
4-hexene is identical to 2-hexene and 5-hexene is identical to 1-hexene. In these cases, the carbon atoms would be numbered from right to left so the lowest number would be used to represent the molecule's name.
In this example: 1-hexene has the double bond between carbon 1 and carbon 2, 2-hexene between carbon 2 and 3, and 3-hexene between carbon 3 and carbon 4.
4-hexene is identical to 2-hexene and 5-hexene is identical to 1-hexene. In these cases, the carbon atoms would be numbered from right to left so the lowest number would be used to represent the molecule's name.
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